Southkraut
Rise, ramble, rest, repeat.
All alliterations are accidental.
User ID: 83
Thanks, that will come in handy when I decide to complicate matters.
Yep, that does the trick. Thanks!
I'm trying to calculate the strength of solar radiation for a given latitude as a simple factor from 1 (equatorial) to 0 (polar), assuming no axial tilt or any other complications. My trigonometry is weak. How do I do this?
Arccos curve looks good. Is it arccos? Arccos(latitude / 90) * (2 / pi) looks pretty decent.
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Isn't that also sort-of the Small-Questions Sunday thread?
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